Question

A uniformly accelerated car acquires a velocity of $72kmph$ in $10s$ starting from rest. Find the distance travelled in this time :

• A. $50m$
• B. $100m$
• C. $150m$
• D. $200m$

Answer 1

The correct option is B $100m$

$u=0$
$v=72kmph=\frac{72\times 1000}{60\times 60}m{s}^{-1}=20m{s}^{-1}$
Acceleration being uniform, average velocity $=\frac{u+v}{2}=10m{s}^{-1}$
$t=10s$
$\therefore$ distance covered = (average velocity $\times$ time)$=(10\times 10)=100m$