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Question

A uniformly charged non-conducting thin hemispherical shall is shown in figure. What is correct direction of net electric field at any point on its open plane surface?
1170296_46c69b0c934e4996925b4ee5cd923020.PNG

A
1
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B
2
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C
3
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D
4
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Solution

The correct option is C 3
Correct direction is 3 because net electric field passing through perpendicular to the surface.
1380425_1170296_ans_1eaee8d1729a4c3b94a8abf6b33ffe0d.jpg

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