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Question

# A uniformly charged ring has linear charge density 4Cm. What is the electric potential at its centre?

A
λϵ0
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B
5λϵ0
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C
λ2ϵ0
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D
λ3ϵ0
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Solution

## The correct option is C λ2ϵ0Let’s look at the situation first. This diagram represents the uniformly charged ring with linear charge density . The radius however is not provided in the question.We can calculate the potential due to a point charge so let’s divide the ring into infinitesimally small parts and try to find potential at O due to one such part. So here, we take a small part dl located at an angle θfrom some reference line subtending dθat the centre. The charge contained in the small element dl, dQ=λ dl and its potential at the centre will be kdQr So dV=kdQr=kλdlr. Since potential is a scalar quantity we don’t have to worry about directions like we did in case of electric field. All we need to do now is integrate this to get the answer. Now in this integral k, λ and r are constants. So the integral becomes ⋅V=kλr∫2π0dl=kλr.2πr=14πϵ0λ2π=λ2ϵ0 Good thing is that we got rid of the radius as it was not provided in the first place.

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