A uniformly charged sphere is placed in such a way that center of sphere coincides with origin, potential of surface is V0. On x axis, we have n points those having potential 5V04, find "n"
A
4
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B
3
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C
2
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D
1
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Solution
The correct option is C 2 The graph of potential will be represented by-
Point A & point B having potential 5V04. Therefore, two points.