A uniformly tapering vessel is filled with a liquid of density 900 $k g / m^{3}$ . The force that acts on the base of the vessel due to the liquid is (g= $10 m s^{- 2}$ )

3.6 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7.2 N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

9.0 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

14.4 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
7.2 N

Force acting on the base

$F = P \times A = h d g A = 0.4 \times 900 \times 10 \times 2 \times 10^{- 3} = 7.2 N$

Suggest Corrections

Similar questions

Q. A uniformly tapering vessel is filled with a liquid of density

900 {kg/m}^{3}

. The force that acts on the base of the vessel due to the liquid (excluding atmospheric force) is : [Take

g = 10 {m/s}^{2}

]

Q. A uniformly tapering vessel shown in the figure is filled with a liquid of density

900 {kg/m}^{3}

. The force that acts on the base of the vessel due to the liquid is (take

g = 10 {m/s}^{2}

)

Q. A unifrom tapering vessel is filled with a liquid of density

900 k g / m^{3}

. The force that acts on the base of the vessel due to the liquid is

(g = 10 m s^{- 2})

A uniformly tapering vessel is filled with a liquid of density 900 $k g / m^{3}$ . The force that acts on the base of the vessel due to the liquid is (g= $10 m s^{- 2}$ )

Q. A uniformly tapering vessel is filled to the top with a liquid of density

900 k g m^{- 3}

. The force that acts on the base of the vessel due to the liquid is

(g = 10 m s^{- 2})

Join BYJU'S Learning Program

A uniformly tapering vessel is filled with a liquid of density 900 kg/m3. The force that acts on the base of the vessel due to the liquid is (g=10ms−2)

The correct option is B 7.2 N Force acting on the base F=P×A=hdgA=0.4×900×10×2×10−3=7.2N

A uniformly tapering vessel is filled with a liquid of density 900 $k g / m^{3}$ . The force that acts on the base of the vessel due to the liquid is (g= $10 m s^{- 2}$ )

The correct option is B
7.2 N

Force acting on the base

$F = P \times A = h d g A = 0.4 \times 900 \times 10 \times 2 \times 10^{- 3} = 7.2 N$