A uniformly tapering vessel is filled with a liquid of density 900 $k g / m^{3}$ . The force that acts on the base of the vessel due to the liquid is (g= $10 m s^{- 2}$ )

$h e i g h t o f t h e v e s s e l = 0.4 m$ $, A r e a o f t h e b o t t o m o f t h e v e s s e l = 2 \times 10^{- 3} m$

3.6 N

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7.2 N

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9.0 N

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14.4 N

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Solution

The correct option is B
7.2 N

Force acting on the base

$F = P \times A = h d g A = 0.4 \times 900 \times 10 \times 2 \times 10^{- 3} = 7.2 N$

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A uniformly tapering vessel is filled with a liquid of density 900 kg/m3. The force that acts on the base of the vessel due to the liquid is (g=10ms−2) heightofthevessel=0.4m ,Areaofthebottomofthevessel=2×10−3m

The correct option is B 7.2 N Force acting on the base F=P×A=hdgA=0.4×900×10×2×10−3=7.2N

A uniformly tapering vessel is filled with a liquid of density 900 $k g / m^{3}$ . The force that acts on the base of the vessel due to the liquid is (g= $10 m s^{- 2}$ )

$h e i g h t o f t h e v e s s e l = 0.4 m$ $, A r e a o f t h e b o t t o m o f t h e v e s s e l = 2 \times 10^{- 3} m$

The correct option is B
7.2 N

Force acting on the base

$F = P \times A = h d g A = 0.4 \times 900 \times 10 \times 2 \times 10^{- 3} = 7.2 N$