A uniformly tapering vessel is filled with a liquid of density 900 kg/ $m^{3}$ . The force that acts on the base of the vessel due to the liquid is $(g = 10 m s^{- 2})$

3.6 N

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7.2 N

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9.0 N

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14.4 N

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Solution

The correct option is B
7.2 N

Force acting on the base F = P $\times$ A = hdgA = 0.4 $\times$ 900 $\times$ 10 $\times$ 2 $\times$ $10^{- 3}$ =7.2 N

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A uniformly tapering vessel is filled with a liquid of density 900 kg/m3. The force that acts on the base of the vessel due to the liquid is (g=10ms−2)

The correct option is B 7.2 N Force acting on the base F = P ×A = hdgA = 0.4 × 900 × 10 × 2 × 10−3=7.2 N

A uniformly tapering vessel is filled with a liquid of density 900 kg/ $m^{3}$ . The force that acts on the base of the vessel due to the liquid is $(g = 10 m s^{- 2})$

The correct option is B
7.2 N

Force acting on the base F = P $\times$ A = hdgA = 0.4 $\times$ 900 $\times$ 10 $\times$ 2 $\times$ $10^{- 3}$ =7.2 N