A unifrom tapering vessel is filled with a liquid of density $900 k g / m^{3}$ . The force that acts on the base of the vessel due to the liquid is $(g = 10 m s^{- 2})$

3.6 N

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7.2 N

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9.0 N

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14.4 N

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Solution

The correct option is A $7.2 N$
$P = ρ g h$
$P = 900 \times 10 \times 0.4$
$P = 3.6 \times 10^{3} N / m^{2}$
Force = P A
$F = 3.6 \times 10^{3} \times 2 \times 10^{- 3}$
$F = 7.2 N$
Hence option 'B' is correct.

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A uniformly tapering vessel is filled with a liquid of density 900 $k g / m^{3}$ . The force that acts on the base of the vessel due to the liquid is (g= $10 m s^{- 2}$ )

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A unifrom tapering vessel is filled with a liquid of density 900 kg/m3. The force that acts on the base of the vessel due to the liquid is (g=10 ms−2)

The correct option is A 7.2 NP=ρghP=900×10×0.4P=3.6×103N/m2Force = P AF=3.6×103×2×10−3F=7.2NHence option 'B' is correct.

A unifrom tapering vessel is filled with a liquid of density $900 k g / m^{3}$ . The force that acts on the base of the vessel due to the liquid is $(g = 10 m s^{- 2})$

The correct option is A $7.2 N$
$P = ρ g h$
$P = 900 \times 10 \times 0.4$
$P = 3.6 \times 10^{3} N / m^{2}$
Force = P A
$F = 3.6 \times 10^{3} \times 2 \times 10^{- 3}$
$F = 7.2 N$
Hence option 'B' is correct.