A atoms are at the corners and B atoms are at the face centres. Therefore, the given compound has an fcc lattice structure.
If two A atoms are missing,
contribution from corner atoms = 6 x 1/8 = 3/4
Contribution of B atoms at face centres = 1/2 x 6 = 3
Formula of the compound = A3/4B3
Simplest formula = A3B12 = AB4