Distinguishing Test of Terminal and Non Terminal Alkynes
A unknown gas...
Question
A unknown gas 'A' decolourises bromine in CCl4 and forms a precipitate with ammoniacal silver nitrate. The gas 'A' is:
A
C2H2
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B
C2H4
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C
C2H6
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D
CH4
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Solution
The correct option is AC2H2 Acetylene gas decolourises bromine in CCl4CH≡CH+2Br2CCl4⟶Br2CH−CHBr2
Acetylene reacts with ammoniacal silver nitrate to produce disilver acetylide. CH≡CH→+2[Ag(NH3)2]NO3→+Ag−C≡C−Ag+↓ppt