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Standard X

Chemistry

Mole Concept and Avogadro's Number

A V dm 3 flas...

Question

A V ${d m}^{3}$ flask contains gas A and another flask of 2V ${d m}^{3}$ contains gas B at the same temperature. If density of gas A is 3.0 g ${d m}^{- 3}$ and of gas B is 1.5 g ${d m}^{- 3}$ and mol. Wt. Of A = $\frac{1}{2}$ mol. Wt. Of B, then the ratio of pressure exerted by gases is

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Solution

The correct option is C

Using PV = $\frac{w}{n}$ RT or P -= $\frac{d}{m}$ RT

For gas A, $P_{A}$ = $\frac{3}{m_{A}}$ $\times$ R $\times$ T

and $P_{B}$ = $\frac{1.5}{m_{s}}$ $\times$ R $\times$ T

$∴$ $\frac{P_{A}}{P_{B}}$ = $\frac{2 \times m_{B}}{m_{A}}$ = $\frac{2 \times 2 \times m_{A}}{m_{A}}$ = 4

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Similar questions

Q. A

0.5 {dm}^{3}

flask contains gas A and a

1 {dm}^{3}

flask contains gas B at the same temperature.
If the density of

A = 3 {g.dm}^{- 3}

, that of

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and the molar mass of

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B, the ratio of pressures exerted by the gases is:

Q. A

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D adiabatic compressionD

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A V dm3 flask contains gas A and another flask of 2V dm3 contains gas B at the same temperature. If density of gas A is 3.0 g dm−3and of gas B is 1.5 g dm−3 and mol. Wt. Of A = 12mol. Wt. Of B, then the ratio of pressure exerted by gases is

The correct option is C Using PV = wn RT or P -= dm RT For gas A, PA = 3mA × R × T and PB = 1.5ms × R × T ∴ PAPB = 2×mBmA = 2×2×mAmA = 4

A V ${d m}^{3}$ flask contains gas A and another flask of 2V ${d m}^{3}$ contains gas B at the same temperature. If density of gas A is 3.0 g ${d m}^{- 3}$ and of gas B is 1.5 g ${d m}^{- 3}$ and mol. Wt. Of A = $\frac{1}{2}$ mol. Wt. Of B, then the ratio of pressure exerted by gases is