Question

A valid Lewis structure cannot be drawn for which of the following compounds?
$(P=15,Si=14,C=6,)$

• A. $P{O}_4^{3-}$
• B. $Si{F}_4$
• C. $C{F}_4$
• D. $C{H}_4$

Answer 1

The correct option is A $P{O}_4^{3-}$

In a valid lewis structure, the central atom should have a complete octet i.e., follow the octet rule.

$\left(a\right)$ Central atom, $P$ has 10 valence electrons.

$\left(b\right)$ Central atom, $Si$ has 8 valence electrons.

$\left(c\right)$ Central atom, $C$ has 8 valence electrons.

$\left(d\right)$ Central atom, $C$ has 8 valence electrons.

Hence, $P{O}_4^{3-}$ violates the octet rule.