wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A value of θ satisfying sin5θ-sin3θ+sinθ=0, such that 0<θ<π2 is


A

π12

loader
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

π6

loader
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

π4

loader
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

π2

loader
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

π6


Explanation for correct answer:

Finding the value.

Step-1: Simplify the given data.

Given, sin5θ-sin3θ+sinθ=0,

sin5θ+sinθ=sin3θ

Step-2: Apply formula sin(c)+sin(d)=2sin(c+d2)cos(c-d2)

2sin5θ+θ2cos5θ-θ2=sin3θ

2sin3θcos2θ=sin3θ

2sin3θcos2θ-sin3θ=0

sin3θ2cos2θ-1=0

sin3θ=0, cos2θ=12

θ=nπ, 2θ=π3 θ=π/6

Hence, option B is correct.


flag
Suggest Corrections
thumbs-up
16
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon
footer-image