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Question

A value of x satisfying 150x35 (Mod 31) is ____.

A
14
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B
22
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C
24
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D
12
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Solution

The correct option is B 24
ab( Mode n)
Means ab is divisible by n
So, 150x35( Mode 31)
150x35 is divisible by 31
5(30x7) is divisible by 31
30x7=31k, where k is any natural number \
x=31k+730=30k+(k+7)30=k+k+730
so smallest positive value of x , k=23
which given x=23+1=24

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