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Byju's Answer
Standard X
Mathematics
Modular Arithmetic and Congruence Modulo
A value of x ...
Question
A value of x satisfying
150
x
≡
35
(Mod 31) is ____.
A
14
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B
22
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C
24
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D
12
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Solution
The correct option is
B
24
a
≡
b
(
Mode
n
)
Means
a
−
b
is divisible by
n
So,
150
x
≡
35
(
Mode 31
)
⇒
150
x
−
35
is divisible by 31
⇒
5
(
30
x
−
7
)
is divisible by 31
30
x
−
7
=
31
k
, where
k
is any natural number \
⇒
x
=
31
k
+
7
30
=
30
k
+
(
k
+
7
)
30
=
k
+
k
+
7
30
so smallest positive value of
x
,
k
=
23
which given
x
=
23
+
1
=
24
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