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Standard XII

Physics

Friction and Horizontal Circular Motion Problems

A van is movi...

Question

A van is moving with a speed of $72 k m / h r$ on level road, where the coefficient of friction between its tyres and road is $0.5$ . The minimum radius of curvature, the road must have for safe driving of van is $(g = 10 m / s^{2})$ :

80 m

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40 m

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20 m

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4 m

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Solution

The correct option is A $80 m$
$v = 72 k m / h r = 72 \times \frac{5}{18} m / s = 20 m / s$
$μ = 0.5$
For safe turning, $μ m g = \frac{m v^{2}}{R_{m i n}}$

or, $R_{m i n} = \frac{20^{2}}{0.5 \times 10} = 80 m$

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Similar questions

Q. Consider a car moving along a straight horizontal road with a speed of

72 k m / h

. If the coefficient of static friction between the tyres and the road is

0.5

, the shortest distance in which the car can be stopped is:
(Take

g = 10 m / s^{2}

)

The maximum speed at which a car can turn round a curve of 400 m radius on a level road is: (Given: coefficient of friction between the tyres and road is 0.1, and g = 10 m/s²)

Q. A car is moving on a circular level road of radius of curvature

300 m

. If the coefficient of friction is

0.5

and taking

g = 10 {m/s}^{2}

, the maximum speed the car can have (in

km/hr

) is

Q. A car is moving on a circular level road of radius of curvature

300 m

. If the coefficient of friction is

0.5

and taking

g = 10 {m/s}^{2}

, the maximum speed the car can have (in

km/hr

) is

Q. A

1200 kg

automobile rounds a level curve of radius

200 m

, on an unbanked road with a velocity of

72 km/h

. What is the minimum coefficient of static friction between the tyres and road in order that the automobile may not skid?

(g = 10 {m/s}^{2})

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A van is moving with a speed of 72 km/hr on level road, where the coefficient of friction between its tyres and road is 0.5. The minimum radius of curvature, the road must have for safe driving of van is (g=10m/s2):

The correct option is A 80 mv=72 km/hr=72×518m/s=20 m/sμ=0.5For safe turning, μmg=mv2Rminor, Rmin=2020.5×10=80 m

A van is moving with a speed of $72 k m / h r$ on level road, where the coefficient of friction between its tyres and road is $0.5$ . The minimum radius of curvature, the road must have for safe driving of van is $(g = 10 m / s^{2})$ :

The correct option is A $80 m$
$v = 72 k m / h r = 72 \times \frac{5}{18} m / s = 20 m / s$
$μ = 0.5$
For safe turning, $μ m g = \frac{m v^{2}}{R_{m i n}}$

or, $R_{m i n} = \frac{20^{2}}{0.5 \times 10} = 80 m$