We have,
Point (2,1) passes through the circle
Then, touches the X-axis So,
Radiusofcircle=Abssicissa
r=2
So the diameter
=2×raidus
=2×2=4
So,
Tangents=Normals=2unit
So, Area of quadrilateral =Length×Breadth
Area=2×=sq.units
Hence, this is the answer.