Formation of a Differential Equation from a General Solution
A variable li...
Question
A variable line passes through a fixed point (x1,y1) and meets the axes at A and B. If the rectangle OAPB be completed, the locus of P is, (O being the origin of the system of axes)
A
(y−y1)2=4(x−x1)
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B
x1x+y1y=1
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C
x2+y2=x21+y21
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D
x22x21+y2y21=1
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Solution
The correct option is Bx1x+y1y=1 Let P be (h,k), then A is (h,0) and B is (0,k). Equation of AB is xh+yk=1.
It passes through (x1,y1) ⇒x1h+y1k=1 Hence, required locus is x1x+y1y=1