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Question

A variable takes the values 0,1,2,3,....n with frequencies nc0,nc1,nc2,nc3,......ncn the mean ¯x=

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Solution

We have, (1+x)n=nC0+nC1.x+.....+nCnxn
Now differentiating both sides with respect to x we get,
n(1+x)n1=nC1+2 nC2.x+.....+n nCn.xn1
Now putting x=1 both sides we get,
n2n1=nC1+2 nC2+...+n nCn......(1).
Now for the problem,
¯¯¯x=0+1. nC1+2. nC2+.....+n. nCn0+1+2+.....+n
or, ¯¯¯x=n2n1n(n+1)2
or, ¯¯¯x=2nn+1.

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