A varies as B and C jointly- if A - 2 when B - 35 and C - 1027- find C when A - 54 and B - 3-

As A varies as B,C jointly then let, A=k(BC) , #160;where k is a constant #160;And A=2,B= 3 5 ,C= 10 27 satisfies the equatio ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Solving Equations with Linear Expressions on One Side and Numbers on the Other Side

A varies as ...

Question

$A$ varies as $B$ and $C$ jointly; if $A = 2$ when $B = \frac{3}{5}$ and $C = \frac{10}{27}$ , find $C$ when $A = 54$ and $B = 3$ .

Open in App

Solution

As $A$ varies as $B, C$ jointly then let,

$A = k (B C)$ , where $k$ is a constant
And $A = 2, B = \frac{3}{5}, C = \frac{10}{27}$ satisfies the equation then,

$2 = k (\frac{3}{5} . \frac{10}{27})$

$2 = k (\frac{2}{9}) \Rightarrow k = 9$

$A = 9 (B C)$

For $A = 54, B = 3$ we have,

$54 = 9 (3 C)$

$54 = 27 C$

$C = 2$

Suggest Corrections

Similar questions

A

varies as

B

and

C

jointly, and

A = 2

when

B = \frac{3}{5}

C = \frac{10}{27}

. The value of

A

, when

B = 2

C = \frac{5}{3}

Q. If

y

varies jointly as

a

and

b

and inversely as the square root of

c

, and

y = 12

when

a = 3, b = 2,

and

c = 64

, find

y

when

a = 5, b = 2,

and

c = 25.

Q. If a varies jointly as b and c and inversely as the square of

d

, and

a = 120

when

b = 5

c = 2

, and

d = 9

, find

a

when

b = 12

c = 9

and

d = 9

Q. If

A

varies as

B

and

C

jointly, while

B

varies as

D^{2}

, and

C

varies inversely as

A

, show that

A

varies as

D

Q. If

A

varies directly as the square root of

B

and inversely as the cube of

C

, and if

A = 3

when

B = 256

and

C = 2

, find

B

when

A = 24

and

C = \frac{1}{2}

Join BYJU'S Learning Program

A varies as B and C jointly; if A=2 when B=35 and C=1027, find C when A=54 and B=3.

As A varies as B,C jointly then let,A=k(BC), where k is a constant And A=2,B=35,C=1027 satisfies the equation then,2=k(35.1027) 2=k(29)⇒k=9A=9(BC)For A=54,B=3 we have,54=9(3C)54=27CC=2

$A$ varies as $B$ and $C$ jointly; if $A = 2$ when $B = \frac{3}{5}$ and $C = \frac{10}{27}$ , find $C$ when $A = 54$ and $B = 3$ .