A variety of pea plant with round yellow seeds and violet flowers (AABBCC) was crossed with a plant having wrinkled green seeds and white flowers (aabbcc). The frequency of plants with genotype AaBbCc in the $F_{2}$ generation would be

\frac{1}{2}

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\frac{1}{8}

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\frac{27}{64}

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\frac{9}{64}

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Solution

The correct option is B $\frac{1}{8}$
Parental generation: $A A B B C C X a a b b c c ↓ F_{1} : A a B b C c$
The cross between F $_{1}$ hybrids is shown below:

From the table, the frequency of plants with genotype AaBbCc in the
F $_{2}$ generation = $\frac{8}{64}$ = $\frac{1}{8}$ .

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A variety of pea plant with round yellow seeds and violet flowers (AABBCC) was crossed with a plant having wrinkled green seeds and white flowers (aabbcc). The frequency of plants with genotype AaBbCc in the F2 generation would be

The correct option is B 18Parental generation: AABBCC X aabbcc ↓F1: AaBbCc The cross between F1 hybrids is shown below: From the table, the frequency of plants with genotype AaBbCc in the F2 generation = 864= 18.

A variety of pea plant with round yellow seeds and violet flowers (AABBCC) was crossed with a plant having wrinkled green seeds and white flowers (aabbcc). The frequency of plants with genotype AaBbCc in the $F_{2}$ generation would be

The correct option is B $\frac{1}{8}$
Parental generation: $A A B B C C X a a b b c c ↓ F_{1} : A a B b C c$
The cross between F $_{1}$ hybrids is shown below:

From the table, the frequency of plants with genotype AaBbCc in the
F $_{2}$ generation = $\frac{8}{64}$ = $\frac{1}{8}$ .