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Question

A varying horizontal force F=at acts on a block of mass m kept on a smooth horizontal surface. An identical block is kept on the first block. The coefficient of friction between the blocks is μ. The time after which the relative sliding between the blocks prevails is

A
2mga
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B
2μmga
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C
μmga
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D
2μmga
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Solution

The correct option is B 2μmga
First, both the block will have same acceleration. As the force is applied on block below so the upper block will have a limiting acceleration which will be equal to the maximum frictional force / mass of upper block.
aUmax=μmg/m=μg

When blocks going together:
Acceleration of both the block, acc=F/(m+m)=at/2m

Relative sliding between the blocks starts when common acceleration reaches the maximum possible acceleration of upper block:
at2m=μgt=2μmga

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