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Question
A →F=(5^i+3^j+2^k) N is applied over a particle with displaces it from its origin to the point →r=(2^i−^j)m. The work done on the particle is joule is
A →F=(5^i+3^j+2^k) N is applied over a particle with displaces it from its origin to the point →r=(2^i−^j)m. The work done on the particle is joule is
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Solution
The correct option is B +7 J
Work done by a force =∫→F.→dr=(5^i+3^j+2^k).(2^i−^j)=7 Joule
Work done by a force =
∫→F.→dr=(5^i+3^j+2^k).(2^i−^j)=7 Joule
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