A vector has 3 units of length and equal components on co-ordinate axes. The vector is
A
(^i+^j+^k)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
√2(^i+^j+^k)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
√3(^i+^j+^k)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
√5(^i+^j+^k)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C√3(^i+^j+^k) Let the vector be a^i+a^j+a^k
Since the length of vector is 3
So, √a2+a2+a2=3
Squaring both sides, a2+a2+a2=9 3a2=9 a=±√3
Required vector =±(√3^i+√3^j+√3^k)