A vector in xy - plane has a magnitude of $25 m$ and magnitude of x - component is $20 m$ . The angle it makes with the positive x - axis is

26^{\circ}

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29^{\circ}

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37^{\circ}

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53^{\circ}

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Solution

The correct option is C $37^{\circ}$
Component of vector in x - direction is given as $20 m$ and from diagram we can say that,
$25 cos θ = 20$
$cos θ = \frac{20}{25} = \frac{4}{5}$

$θ = 37^{\circ}$

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A vector in xy - plane has a magnitude of 25 m and magnitude of x - component is 20 m. The angle it makes with the positive x - axis is

The correct option is C 37∘Component of vector in x - direction is given as 20 m and from diagram we can say that, 25cosθ=20 cosθ=2025=45 θ=37∘

A vector in xy - plane has a magnitude of $25 m$ and magnitude of x - component is $20 m$ . The angle it makes with the positive x - axis is

The correct option is C $37^{\circ}$
Component of vector in x - direction is given as $20 m$ and from diagram we can say that,
$25 cos θ = 20$
$cos θ = \frac{20}{25} = \frac{4}{5}$

$θ = 37^{\circ}$