wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A vector of magnitude 2 along a bisector of the angle between the two vectors 2i2j+k and i+2j2k is

A
210(3ik)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
126(i4j+3k)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
226(i4j+3k)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct options are
C 226(i4j+3k)
D 210(3ik)
The vector along the angle bisector is obtained by the sum and difference of unit vectors along both arms.

Thus, 13(2i2j+k±i+2j2k)=i13k and 13i43j+k

Now for the vector of magnitude 2, we multiply the unit vector in that direction by 2 and get 210(3ik) and 226(i4j+3k)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Application of Vectors - Lines
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon