A vector A- has magnitude of 3 units and it points towards east while another vector B- has magnitude of 4 units and it points towards north-The ratio between A-B- and -A-B- is-

The magnitudes of vectors $\to A, \to B a n d \to C$ are 3, 4 and 5 units respectively. If $\to A + \to B = \to C$ , the angle between $\to A$ and $\to B$ is

Q. A vector

\to A

points vertically upward and

\to B

points towards north. The vector product

\to A \times \to B

is:-

Q. Vector

\to a

has components

a_{x} = 3, a_{y} = 4

. Find the components of a vector

\to c

which is perpendicular to

\to a

and has a magnitude of

5

units.

The magnitude of vector $\to A, \to B$ and $\to C$ are respectively 12, 5 and 13 units and $\to A + \to B = \to C$ then the angle between $\to A$ and $\to B$ is

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A vector →A has magnitude of 3 units and it points towards east while another vector →B has magnitude of 4 units and it points towards north.The ratio between →A⋅→B and |→A×→B| is:

The correct option is C 0:12A and B are perpendicular to each other. Hence A.B is zero and |→A×→B| =12. Hence answer will be 0:12

A vector $\to A$ has magnitude of $3$ units and it points towards east while another vector $\to B$ has magnitude of $4$ units and it points towards north.The ratio between $\to A \cdot \to B$ and $| \to A \times \to B |$ is:

The correct option is C 0:12
A and B are perpendicular to each other. Hence $A . B$ is zero and | $\to A \times \to B$ | $= 12$ .
Hence answer will be $0 : 12$