A vector →a is turned without a change in its length through a small angle dθ. The value of |△→a| and △a are respectively:
A
0,adθ
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B
adθ,0
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C
0,0
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D
None of these
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Solution
The correct option is Badθ,0 From the figure |→OA|=a and |→OB|=a Also from triangle rule →OB−→OA=→AB=Δ→a ⇒|Δ→a|=AB using angle =arcradius ⇒AB=a.dθ So |Δ→a|=adθ Δa means change in magnitude of vector i.e.|→OB|−|→OA| ⇒a−a=0 So Δa=0