A vehicle is accelerating on a staright road.Its velocity at any instant is 30 $k m h^{- 1}$ ,after 2 s, it is 33.6 $k m h^{- 1}$ and after further 2 s, it is 37.2 $k m h^{- 1}$ . Find the acceleration of vehicle in $m s^{- 2}$ . Is the accleration uniform?

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Solution

First part:

Change in velocity = 33.6 kmph - 30 kmph = 3.6 kmph = $3.6 \times \frac{5}{18} m / s = 1 m / s$

So, acceleration = Change in velocity / Time $= \frac{1 m / s}{2 s} = 0.5 m / s^{2}$

Second part:

Change in velocity = 37.2 kmph - 33.6 kmph = 3.6 kmph = 1m/s

So, acceleration = Change in velocity / Time $= \frac{1 m / s}{2 s} = 0.5 m / s^{2}$

Hence, the acceleration is uniform.

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A vehicle is accelerating on a staright road.Its velocity at any instant is 30 km h−1,after 2 s, it is 33.6 km h−1 and after further 2 s, it is 37.2 km h−1. Find the acceleration of vehicle in m s−2. Is the accleration uniform?

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