Question

A vehicle is moving with a velocity v on a curved road of width b and radius of curvature R. For counteracting the centrifugal force on the vehicle, the difference in elevation required in between the outer and inner edges of the rod is

• A. $v^{2}b/Rg$
• B. $vb/Rg$
• C. $v{b}^2/Rg$
• D. $vb/R^{2}g$

Answer 1

The correct option is A $v^{2}b/Rg$

From FBD

$N\cos \theta =mgN\sin \theta =\frac{m{v}^2}{R}\tan \theta =\frac{v^2}{rg}=\frac{h}{b}\Rightarrow =\frac{b{v}^2}{rg}$