A vehicle moving at a speed of 15 m/s is stopped by applying brakes which produce a uniform acceleration of -0.5 $m / s^{2}$ . The distance covered by the vehicle before it stops is:

100 m

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200 m

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250 m

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225 m

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Solution

The correct option is D 225 m
Initial velocity or speed $u = 15 m / s$
The acceleration $a = - 0.5 m / s^{2}$
When vehicle stops its final velocity becomes zero $v = 0$
By applying equation of motion
$v^{2} = u^{2} + 2 a S$
$0 = 225 - 2 \times 0.5 S S = \frac{225}{2 \times 0.5} = 225 m$

Option D is correct.

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A vehicle moving at a speed of 15 m/s is stopped by applying brakes which produce a uniform acceleration of -0.5 m/s2. The distance covered by the vehicle before it stops is:

The correct option is D 225 mInitial velocity or speed u=15m/sThe acceleration a=−0.5m/s2When vehicle stops its final velocity becomes zero v=0By applying equation of motion v2=u2+2aS0=225−2×0.5SS=2252×0.5=225mOption D is correct.

A vehicle moving at a speed of 15 m/s is stopped by applying brakes which produce a uniform acceleration of -0.5 $m / s^{2}$ . The distance covered by the vehicle before it stops is: