Question

# A vehicle of $50\mathrm{quintal}$ climbs up a hill of $10\mathrm{m}$. The potential energy gained by it is (take $\mathrm{g}=10\mathrm{m}/{\mathrm{s}}^{2}$).

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Solution

## Step 1: Given informationMass, $\mathrm{m}=50\mathrm{quintal}$ $=50×100\phantom{\rule{0ex}{0ex}}=5000\mathrm{kg}$Height, $\mathrm{h}=10\mathrm{m}$Acceleration due to gravity, $\mathrm{g}=10\mathrm{m}/{\mathrm{s}}^{2}$Step 2: To findWe have to find the potential energy gained by the vehicle.Step 3: CalculationWe know the formula,Potential energy, $\mathrm{P}=\mathrm{mgh}$By substituting the values, we get $=5000×10×10\phantom{\rule{0ex}{0ex}}=5×{10}^{5}\mathrm{J}$Therefore, the gained potential energy is $5×{10}^{5}\mathrm{J}$.

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