Question

A vehicle of $50\mathrm{quintal}$ climbs up a hill of $10\mathrm{m}$. The potential energy gained by it is (take $\mathrm{g}=10\mathrm{m}/{\mathrm{s}}^2$).

Answer 1

Step 1: Given information

Mass, $\mathrm{m}=50\mathrm{quintal}$

$$\begin{gathered} =50\times 100 \\ =5000\mathrm{kg} \end{gathered}$$

Height, $\mathrm{h}=10\mathrm{m}$

Acceleration due to gravity, $\mathrm{g}=10\mathrm{m}/{\mathrm{s}}^2$

Step 2: To find

We have to find the potential energy gained by the vehicle.

Step 3: Calculation

We know the formula,

Potential energy, $\mathrm{P}=\mathrm{mgh}$

By substituting the values, we get

$$\begin{gathered} =5000\times 10\times 10 \\ =5\times {10}^5\mathrm{J} \end{gathered}$$

Therefore, the gained potential energy is $5\times {10}^5\mathrm{J}$.