Question

A vehicle of mass $100kg$ is moving with a velocity of $5m/s$. To stop it in $\frac{1}{10}s$ the required force in opposite direction is:

• A. $5000N$
• B. $500N$
• C. $50N$
• D. $1000N$

Answer 1

The correct option is A $5000N$

$F=\frac{\Delta P}{\Delta t}=\frac{m(V_2-V_1)}{\Delta t}=\frac{100(0-5)\times 10}{1}=-5000N$