Question

A vehicle of mass $1000kg$ is moving with a velocity of $15m{s}^{-1}$. It is brought to rest by applying brakes and locking the wheels. If the sliding friction between the tires and the rod is $6000N$, distance moved by the vehicle before coming to rest is:

• A. 37.5 m
• B. 18.75 m
• C. 75 m
• D. 15 m

Answer 1

Answer: (B)

18.75 m

$F.S=KE$
$\therefore S=\frac{KE}{F}=\frac{\frac{1}{2}\times 1000\times {15}^2}{6000}=18.75m$