A vehicle of mass 1000 kg moving with a velocity of 10 m/s comes to rest because of a breaking force after transversing a distance of 10 m. The work done on the vehicle is

50 kJ

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60 kJ

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75 kJ

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100 kJ

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Solution

The correct option is A 50 kJ
u = 10, v = 0, s = 10

$v^{2} = u^{2} + 2 a s$

$0 = 10^{2} - 2 \times a \times 10$

$∴$ $a = \frac{100}{2 \times 10} = 5 m / s e c^{2}$

$F = m a = 1000 \times 5 = 5000 N$

Work done = Force $\times$ displacement

$= 5000 \times 10 = 50 k J$

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A vehicle of mass 1000 kg moving with a velocity of 10 m/s comes to rest because of a breaking force after transversing a distance of 10 m. The work done on the vehicle is

The correct option is A 50 kJu = 10, v = 0, s = 10 v2=u2+2as 0=102−2×a×10 ∴ a=1002×10=5m/sec2 F=ma=1000×5=5000N Work done = Force × displacement =5000×10=50kJ

The correct option is A 50 kJ
u = 10, v = 0, s = 10

$v^{2} = u^{2} + 2 a s$

$0 = 10^{2} - 2 \times a \times 10$

$∴$ $a = \frac{100}{2 \times 10} = 5 m / s e c^{2}$

$F = m a = 1000 \times 5 = 5000 N$

Work done = Force $\times$ displacement

$= 5000 \times 10 = 50 k J$