Question

A vehicle of mass M is moving on a rough horizontal road with a momentum P. If the coefficient of friction between the tyres and the road is $\mu$ , then the stopping distance is

• A. $\frac{P}{2\mu Mg}$
• B. $\frac{P^2}{2\mu Mg}$
• C. $\frac{P^2}{2\mu M^{2}g}$
• D. $\frac{P}{2\mu M^{2}g}$

Answer 1

The correct option is C $\frac{P^2}{2\mu M^{2}g}$

We know,

$F.S=\frac{p^2}{2M}$
Also,

Frictional force,
$F=\mu Mg$

$\therefore S=\frac{p^2}{2M.\mu Mg}$

$\therefore S=\frac{p^2}{2M^2.\mu g}$