A vehicle travelling on dry, level pavement at 80 kmph had the brakes applied. The vehicle travelled 76.5 m before stopping. What is the coefficient of friction that has developed ?
A
0.2
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B
0.3
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C
0.33
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D
0.4
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Solution
The correct option is C 0.33 After the application of brakes, the work done against the frictional force for stopping the vehicle will be equal to the kinetic energy of the vehicle. 12mV2=μmg.l 12(80×100036000)2=μ×9.81×76.5 μ=0.33