A Vernier caliper has 1 mm marks on the main scale. It has 20 equal divisions on the Vernier scale which match with 16 main scale divisions. For this Vernier caliper, the least count is:

0.02 mm

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0.05 mm

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0.1 mm

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0.2 mm

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Solution

The correct option is D
0.2 mm

Least count is the difference between one main scale division and vernier scale division.

$20 V S D = 16 M S D$
$1 V S D = \frac{16}{20} M S D$
$L . C . = 1 M S D - 1 V S D$
$L . C . = \frac{4}{20} M . S . D$
$L . C . = \frac{1}{5} \times 1 m m = 0.2 m m$

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A Vernier caliper has 1 mm marks on the main scale. It has 20 equal divisions on the Vernier scale which match with 16 main scale divisions. For this Vernier caliper, the least count is:

The correct option is D 0.2 mm Least count is the difference between one main scale division and vernier scale division. 20 VSD=16 MSD 1 VSD=1620 MSD L.C.=1 MSD−1 VSD L.C.=420 M.S.D L.C.=15×1 mm=0.2 mm

The correct option is D
0.2 mm

Least count is the difference between one main scale division and vernier scale division.

$20 V S D = 16 M S D$
$1 V S D = \frac{16}{20} M S D$
$L . C . = 1 M S D - 1 V S D$
$L . C . = \frac{4}{20} M . S . D$
$L . C . = \frac{1}{5} \times 1 m m = 0.2 m m$