A Vernier caliper has 1 mm marks on the main scale. It has 20 equal divisions on the Vernier scale which match with 16 main scale divisions. For this Vernier caliper, the least count is:

0.02 mm

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0.05 mm

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0.1 mm

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0.2 mm

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Solution

The correct option is D
0.2 mm

Given,
20 V.S.D = 16 M.S.D
1 M.S.D = 1 mm

1 V.S.D = $\frac{16}{20}$ M.S.D

Least count is the difference between one main scale division and vernier scale division.
L.C. = 1 MSD - 1 VSD
L.C. = 1 MSD - $\frac{16}{20}$ M.S.D
L.C. = $\frac{1}{5}$ M.S.D
L.C. = $\frac{1}{5} \times 1 m m$
L.C. = 0.2 mm

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A Vernier caliper has 1 mm marks on the main scale. It has 20 equal divisions on the Vernier scale which match with 16 main scale divisions. For this Vernier caliper, the least count is:

The correct option is D 0.2 mm Given, 20 V.S.D = 16 M.S.D 1 M.S.D = 1 mm 1 V.S.D = 1620M.S.D Least count is the difference between one main scale division and vernier scale division. L.C. = 1 MSD - 1 VSD L.C. = 1 MSD - 1620M.S.D L.C. = 15M.S.D L.C. = 15×1 mm L.C. = 0.2 mm