A vernier caliper has 1 mm marks on the math scale. It has 20 equal divisions on the vernier scale (VSD) which match with 18 main scale divisions (MSD). What is the least count (L.C) for this vernier caliper?

(A) 0.1 mm
(B) 0.01 mm
(C) 0.2 mm
(D) 0.02 mm

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Solution

Dear Student,
$L e a s t c o u n t o f v e r n i e r s c a l e = \frac{V S D - M S D}{V S D} \times m a i n s c a l e l e a s t c o u n t = \frac{20 - 18}{20} \times 1 m m = . 1 m m$
Regards

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A vernier caliper has 1 mm marks on the math scale. It has 20 equal divisions on the vernier scale (VSD) which match with 18 main scale divisions (MSD). What is the least count (L.C) for this vernier caliper? (A) 0.1 mm (B) 0.01 mm (C) 0.2 mm (D) 0.02 mm

Dear Student, Least count of vernier scale =VSD-MSDVSD×main scale least count=20-1820×1mm=.1mm Regards

A vernier caliper has 1 mm marks on the math scale. It has 20 equal divisions on the vernier scale (VSD) which match with 18 main scale divisions (MSD). What is the least count (L.C) for this vernier caliper?

(A) 0.1 mm
(B) 0.01 mm
(C) 0.2 mm
(D) 0.02 mm

Dear Student,
$L e a s t c o u n t o f v e r n i e r s c a l e = \frac{V S D - M S D}{V S D} \times m a i n s c a l e l e a s t c o u n t = \frac{20 - 18}{20} \times 1 m m = . 1 m m$
Regards