A vernier caliper has 20 divisions on the vernier scale, which coincide with 19 on the main scale. The least count of the instrument is 0.1 mm. The main scale divisions are of :

0.5 m m

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1 m m

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2 m m

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\frac{1}{4} m m

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Solution

The correct option is B $2 m m$
$0.1 = (1 - \frac{19}{20}) M S D \Rightarrow \frac{1}{10} = \frac{1}{20} \times 1 M S D$
$\Rightarrow 1 M S D = 0.1 \times 20 = 2 m m$

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A vernier caliper has 20 divisions on the vernier scale, which coincide with 19 on the main scale. The least count of the instrument is 0.1 mm. The main scale divisions are of :

The correct option is B 2 mm0.1=(1−1920)MSD⇒110=120×1MSD⇒1MSD=0.1×20=2 mm

The correct option is B $2 m m$
$0.1 = (1 - \frac{19}{20}) M S D \Rightarrow \frac{1}{10} = \frac{1}{20} \times 1 M S D$
$\Rightarrow 1 M S D = 0.1 \times 20 = 2 m m$