A vernier calliper has 25 divisions on its vernier scale for every 35 divisions on its main scale. If 1 cm on the main scale is split into 12 units, the least count of the calliper will be.
A
0.0333cm
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B
0.0333mm
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C
0.333cm
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Solution
The correct option is B0.0333mm Given: The no. of vernier scale divisions, n=25 The value of one main scale division, x=112=0.08333cm The least count of the callipers, L.C.=xn=0.0833325=0.00333cm 1cm=10mm ⟹0.00333cm= =0.00333×10mm=0.0333mm