Question

A vernier calliper has 25 divisions on its vernier scale for every 35 divisions on its main scale. If 1 cm on the main scale is split into 12 units, the least count of the calliper will be.

• A. $0.0333cm$
• B. $0.0333mm$
• C. $0.333cm$

Answer 1

The correct option is B $0.0333mm$

Given:
The no. of vernier scale divisions, $n=25$
The value of one main scale division, $x=\frac{1}{12}=0.08333cm$
The least count of the callipers, $\text{L.C.}=\frac{x}{n}=\frac{0.08333}{25}=0.00333cm$
$1cm=10mm$
$⟹0.00333cm=$
$=0.00333\times 10mm=0.0333mm$