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Question

A vernier callipers has 25 divisions on its vernier scale for every 35 divisions on its main scale. If 1 cm on the main scale is split into 12 units, the least count of the callipers will be


A
0.0333 cm
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B
33.33 mm
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C
0.0333 mm
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D
0.333 cm
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Solution

The correct option is A 0.0333 mm
Given:
The no. of vernier scale divisions, n=25
The value of one main scale division, x=112=0.08333 cm
The least count of the callipers, L.C.=xn=0.0833325=0.00333 cm
1 cm=10 mm 0.00333 cm=
=0.00333×10 mm=0.0333 mm

Physics

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