A vernier having a positive zero correction of $+ 5$ is used to measure the side of $2 c m$ cube. The length as measured by the vernier will be: (use LC $= 0.01 c m$ )

1.95 c m

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2 c m

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2.05 c m

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Solution

The correct option is A $2.05 c m$
As zero error is positive zero error so it will be subtract from the main reading for getting actual reading. The positive zero error reading $= 5 \times L . c = 5 \times 0.01 = 0.05 c m$
Thus, vernier will be measured extra 0.05 cm than the actual length.
Hence, the value of length measured by vernier $= 2 + 0.05 = 2.05 c m$

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A vernier having a positive zero correction of +5 is used to measure the side of 2cm cube. The length as measured by the vernier will be: (use LC =0.01cm)

A vernier having a positive zero correction of $+ 5$ is used to measure the side of $2 c m$ cube. The length as measured by the vernier will be: (use LC $= 0.01 c m$ )