Question

A vertical current carrying conductor of length 2 m placed in horizontal uniform magnetic field of 5T experiences a force of 60 N. The current flowing through the conductor is

• A. 6 A
• B. 12 A
• C. 24 A
• D. 8 A

Answer 1

The correct option is A 6 A

Length of the conductor, l = 2 m
Magnetic field, B = 5 T
Force on the conductor, F = 60 N
Angle between conductor and magnetic field (B), $\theta ={90}^{\circ }$
Force experienced by given conductor carrying current i, $F=ilBsin\theta =ilB(\because sin{90}^{\circ }=1)$
$\Rightarrow i=\frac{F}{IB}=\frac{60}{2\times 5}$
Hence, the correct answer is option (1).