Question

A vertical cut is made in a clay deposit having unit weight $19.5kN/m^3$. The unconfined compressive strength is $50kN/m^2$. What will be the maximum height of cut which can be temporarily supported? (Taylor stability number = 0.317)

• A. 2 m
• B. 4 m
• C. 6 m
• D. 8 m

Answer 1

The correct option is B 4 m

Taylor stability no., $S_n=\frac{C}{F_C\gamma H}$

Given, $q_u=50kN/m^2$

$C=\frac{q_u}{2}$

$=25kN/m^2$

For critical height, $F_C=1$

$0.317=\frac{25}{1\times 19.5\times H_C}$

$H_C=4.04m$