A vertical cut is to be made in a soil mass having cohesion c- angle of internal friction - and unit weight - Considering Ka and Kp as the coefficient of active and passive earth pressures- respectively- the maximum depth of unsupported excavation is

0 = K_aγ Z_0 2C√(K_a) Z_0=2Cγ√(K_a)⇒ Z_max=4Cγ√(K_a) ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Other

Foundation Engineering

Coulomb Wedge Theory

A vertical cu...

Question

A vertical cut is to be made in a soil mass having cohesion c, angle of internal friction $ϕ$ , and unit weight $γ$ . Considering $K_{a} a n d K_{p}$ as the coefficient of active and passive earth pressures, respectively, the maximum depth of unsupported excavation is

\frac{4 c}{γ \sqrt{K_{p}}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2 c \sqrt{K_{p}}}{γ}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{4 C \sqrt{K_{a}}}{γ}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{4 c}{γ \sqrt{K_{a}}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $\frac{4 c}{γ \sqrt{K_{a}}}$
$0 = K_{a} γ Z_{0} - 2 C \sqrt{K_{a}}$

$Z_{0} = \frac{2 C}{γ \sqrt{K_{a}}} \Rightarrow Z_{m a x} = \frac{4 C}{γ \sqrt{K_{a}}}$

Suggest Corrections

Similar questions

Q. An unsupported excavation is made to the maximum possible depth in a clay soil having

γ_{t}

18 k N / m^{3}

C = 100 k N / m^{2}

ϕ = 30^{\circ}

. The active earth pressure, according to Rankine's theory, at the base level of the excavation is

Q. In a cohesionless soil deposit having a unit weight of

1.5 t / m^{3}

and an angle of internal friction of

30^{\circ},

the active and passive lateral earth pressure intensities

(i n t / m^{2})

at a depth of 10 m will, respectively, be

Q. The value of active earth pressure coefficient for a cohesion less soil having effective angle of internal friction

40^{\circ}

is . (Round upto three decimal places)

The intensity of passive earth pressure at a depth of 5 m in a cohesion less soil with an angle of internal friction of $30^{\circ}$ when water rises to ground level is $k N / m^{2}$ . Take saturated unit weight of sand as $21 k N / m^{3}$ and $γ_{w} = 9.81 k N / m^{3}$ .

Q. Assertion (A): The safe height

(2 z_{0})

to which an unsupported vertical cut in clay be made is

4 c / γ .

Reason (R): Active earth pressure of cohesive backfill shows that the negative pressure (tension) is developed at top level. This tension decrease to zero at depth

z_{0}

and total net pressure up to a depth

2 z_{0}

is zero.

Join BYJU'S Learning Program

A vertical cut is to be made in a soil mass having cohesion c, angle of internal friction ϕ, and unit weight γ. Considering KaandKp as the coefficient of active and passive earth pressures, respectively, the maximum depth of unsupported excavation is

The correct option is D 4cγ√Ka0=KaγZ0−2C√Ka Z0=2Cγ√Ka⇒Zmax=4Cγ√Ka

A vertical cut is to be made in a soil mass having cohesion c, angle of internal friction $ϕ$ , and unit weight $γ$ . Considering $K_{a} a n d K_{p}$ as the coefficient of active and passive earth pressures, respectively, the maximum depth of unsupported excavation is

The correct option is D $\frac{4 c}{γ \sqrt{K_{a}}}$
$0 = K_{a} γ Z_{0} - 2 C \sqrt{K_{a}}$

$Z_{0} = \frac{2 C}{γ \sqrt{K_{a}}} \Rightarrow Z_{m a x} = \frac{4 C}{γ \sqrt{K_{a}}}$