Question

A vertical electric field of magnitude $4.00\times {10}^{5}N{C}^{-1}$ just prevents a water droplet of mass $1.00\times {10}^{-4}$ kg from falling.Find the charge on the droplet.

Answer 1

$4\times {10}^5\left(q\right)=1\times {10}^{-4}\times 10$

$q=\frac{{10}^{-4}\times 10}{4\times {10}^5}$

$q=2.5\times {10}^{-9}C$

We get, $q=2.5\times {10}^{-9}C.$