Question

A vertical flagstaff stands on a horizontal plane.From a point distance $150$ metres from its foot the angle of elevation of its top is found to be ${30}^0$ ;

find the height of the flagstaff.

Answer 1

Let $AB$ be the vertical flagstaff of height $h$.

As we know that,

$\tan \theta =\frac{\text{Perpendicular}}{\text{Base}}$

Now, in $△ABC$

$\tan 30°=\frac{AB}{BC}$

$\Rightarrow \frac{1}{\sqrt{3}}=\frac{h}{150}$

$\Rightarrow h=\frac{150}{\sqrt{3}}=50\sqrt{3}$

Hence the height of the flagstaff is $50\sqrt{3}m$.