Question

A vertical pole of $5.6m$ height casts a shadow $3.2m$ long. At the same time find the length of the shadow cast by another pole $10.5m$ high.

Answer 1

pole 1 height is $5.6m=h_1$

Shadow height $=3.2m=s_1$

another pole 2 $h_2=10.5m$

Let shadow of pole $2=s_2$

$\frac{h_1}{h_2}=\frac{s_1}{s_2}$

$\Rightarrow \frac{5.6}{10.5}=\frac{3.2}{x}$

$\Rightarrow x=\frac{10.5\times 3.2}{5.6}$

$x=6m$